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10034413143 = 33344804381
BaseRepresentation
bin10010101100001100…
…01111111001010111
3221220022112000002020
421112012033321113
5131022302210033
64335412144223
7503443050546
oct112606177127
927808460066
1010034413143
11428a18a127
121b40608073
13c3bb79091
146b296015d
153dae096b3
hex25618fe57

10034413143 has 4 divisors (see below), whose sum is σ = 13379217528. Its totient is φ = 6689608760.

The previous prime is 10034413139. The next prime is 10034413177. The reversal of 10034413143 is 34131443001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10034413143 - 22 = 10034413139 is a prime.

It is a super-2 number, since 2×100344131432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10034413043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672402188 + ... + 1672402193.

It is an arithmetic number, because the mean of its divisors is an integer number (3344804382).

Almost surely, 210034413143 is an apocalyptic number.

10034413143 is a deficient number, since it is larger than the sum of its proper divisors (3344804385).

10034413143 is an equidigital number, since it uses as much as digits as its factorization.

10034413143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3344804384.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 10034413143 its reverse (34131443001), we get a palindrome (44165856144).

The spelling of 10034413143 in words is "ten billion, thirty-four million, four hundred thirteen thousand, one hundred forty-three".

Divisors: 1 3 3344804381 10034413143