Base | Representation |
---|---|
bin | 101110101110011111… |
… | …1100011010010110000 |
3 | 100121000011201020202020 |
4 | 1131130333203102300 |
5 | 3121001132130222 |
6 | 114033024551440 |
7 | 10151425265055 |
oct | 1353477432260 |
9 | 317004636666 |
10 | 100344411312 |
11 | 39612893452 |
12 | 17545182580 |
13 | 9601c89c12 |
14 | 4bdcab502c |
15 | 29245bc65c |
hex | 175cfe34b0 |
100344411312 has 40 divisors (see below), whose sum is σ = 259790347056. Its totient is φ = 33374939136.
The previous prime is 100344411301. The next prime is 100344411317. The reversal of 100344411312 is 213114443001.
It is a super-3 number, since 3×1003444113123 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (100344411317) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2265273 + ... + 2309144.
Almost surely, 2100344411312 is an apocalyptic number.
100344411312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
100344411312 is an abundant number, since it is smaller than the sum of its proper divisors (159445935744).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
100344411312 is a wasteful number, since it uses less digits than its factorization.
100344411312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4574885 (or 4574879 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 100344411312 its reverse (213114443001), we get a palindrome (313458854313).
The spelling of 100344411312 in words is "one hundred billion, three hundred forty-four million, four hundred eleven thousand, three hundred twelve".
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