Base | Representation |
---|---|
bin | 11101001110000111010… |
… | …10101100111111110001 |
3 | 10112222112012012012122202 |
4 | 32213003222230333301 |
5 | 112422203043201231 |
6 | 2045122541312545 |
7 | 132352210210232 |
oct | 16470352547761 |
9 | 3488465165582 |
10 | 1004010131441 |
11 | 3578865aa009 |
12 | 142700b65755 |
13 | 738a7026895 |
14 | 36846c77089 |
15 | 1b1b383d5cb |
hex | e9c3aacff1 |
1004010131441 has 2 divisors, whose sum is σ = 1004010131442. Its totient is φ = 1004010131440.
The previous prime is 1004010131417. The next prime is 1004010131459. The reversal of 1004010131441 is 1441310104001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 754994161216 + 249015970225 = 868904^2 + 499015^2 .
It is an emirp because it is prime and its reverse (1441310104001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1004010131441 - 238 = 729132224497 is a prime.
It is not a weakly prime, because it can be changed into another prime (1004010131401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502005065720 + 502005065721.
It is an arithmetic number, because the mean of its divisors is an integer number (502005065721).
Almost surely, 21004010131441 is an apocalyptic number.
It is an amenable number.
1004010131441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004010131441 is an equidigital number, since it uses as much as digits as its factorization.
1004010131441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1004010131441 its reverse (1441310104001), we get a palindrome (2445320235442).
The spelling of 1004010131441 in words is "one trillion, four billion, ten million, one hundred thirty-one thousand, four hundred forty-one".
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