Base | Representation |
---|---|
bin | 101110110000001100… |
… | …0001011101110110011 |
3 | 100121011010120102020212 |
4 | 1131200120023232303 |
5 | 3121110201400201 |
6 | 114042414054335 |
7 | 10153015055645 |
oct | 1354030135663 |
9 | 317133512225 |
10 | 100401200051 |
11 | 39641950699 |
12 | 175601aa3ab |
13 | 9610981319 |
14 | 4c06458895 |
15 | 2929588abb |
hex | 176060bbb3 |
100401200051 has 2 divisors, whose sum is σ = 100401200052. Its totient is φ = 100401200050.
The previous prime is 100401200023. The next prime is 100401200069. The reversal of 100401200051 is 150002104001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100401200051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100401199999 and 100401200035.
It is not a weakly prime, because it can be changed into another prime (100401200071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50200600025 + 50200600026.
It is an arithmetic number, because the mean of its divisors is an integer number (50200600026).
Almost surely, 2100401200051 is an apocalyptic number.
100401200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
100401200051 is an equidigital number, since it uses as much as digits as its factorization.
100401200051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 14.
Adding to 100401200051 its reverse (150002104001), we get a palindrome (250403304052).
The spelling of 100401200051 in words is "one hundred billion, four hundred one million, two hundred thousand, fifty-one".
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