Base | Representation |
---|---|
bin | 1001001000011010010111… |
… | …0011111101101011111011 |
3 | 1022112211022020220102220021 |
4 | 2102012211303331223323 |
5 | 2303444131312332103 |
6 | 33204211225111311 |
7 | 2054242354403014 |
oct | 222064563755373 |
9 | 38484266812807 |
10 | 10040120433403 |
11 | 3220a9a26a4a5 |
12 | 1161a14028537 |
13 | 57aa19157048 |
14 | 269d316ca00b |
15 | 1262772b8bbd |
hex | 921a5cfdafb |
10040120433403 has 4 divisors (see below), whose sum is σ = 10116762574248. Its totient is φ = 9963478292560.
The previous prime is 10040120433391. The next prime is 10040120433439. The reversal of 10040120433403 is 30433402104001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10040120433403 - 213 = 10040120425211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10040120433493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38321070226 + ... + 38321070487.
It is an arithmetic number, because the mean of its divisors is an integer number (2529190643562).
Almost surely, 210040120433403 is an apocalyptic number.
10040120433403 is a deficient number, since it is larger than the sum of its proper divisors (76642140845).
10040120433403 is an equidigital number, since it uses as much as digits as its factorization.
10040120433403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76642140844.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 10040120433403 its reverse (30433402104001), we get a palindrome (40473522537404).
The spelling of 10040120433403 in words is "ten trillion, forty billion, one hundred twenty million, four hundred thirty-three thousand, four hundred three".
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