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1004031023953 is a prime number
BaseRepresentation
bin11101001110001001110…
…10011001101101010001
310112222120122111122210111
432213010322121231101
5112422223420231303
62045125005201321
7132352552614316
oct16470472315521
93488518448714
101004031023953
11357897379951
12142707b60241
13738ab460309
1436849954d0d
151b1b55b8b6d
hexe9c4e99b51

1004031023953 has 2 divisors, whose sum is σ = 1004031023954. Its totient is φ = 1004031023952.

The previous prime is 1004031023921. The next prime is 1004031024043. The reversal of 1004031023953 is 3593201304001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 804594648064 + 199436375889 = 896992^2 + 446583^2 .

It is a cyclic number.

It is not a de Polignac number, because 1004031023953 - 25 = 1004031023921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1004031021953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502015511976 + 502015511977.

It is an arithmetic number, because the mean of its divisors is an integer number (502015511977).

Almost surely, 21004031023953 is an apocalyptic number.

It is an amenable number.

1004031023953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004031023953 is an equidigital number, since it uses as much as digits as its factorization.

1004031023953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 1004031023953 its reverse (3593201304001), we get a palindrome (4597232327954).

The spelling of 1004031023953 in words is "one trillion, four billion, thirty-one million, twenty-three thousand, nine hundred fifty-three".