100404340331 has 2 divisors, whose sum is σ = 100404340332. Its totient is φ = 100404340330.

The previous prime is 100404340313. The next prime is 100404340427. The reversal of 100404340331 is 133043404001.

Together with previous prime (100404340313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100404340331 is a prime.

It is a super-2 number, since 2×100404340331² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 100404340297 and 100404340306.

It is not a weakly prime, because it can be changed into another prime (100404300331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50202170165 + 50202170166.

It is an arithmetic number, because the mean of its divisors is an integer number (50202170166).

Almost surely, 2^100404340331 is an apocalyptic number.

100404340331 is a deficient number, since it is larger than the sum of its proper divisors (1).

100404340331 is an equidigital number, since it uses as much as digits as its factorization.

100404340331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 100404340331 its reverse (133043404001), we get a palindrome (233447744332).

The spelling of 100404340331 in words is "one hundred billion, four hundred four million, three hundred forty thousand, three hundred thirty-one".