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10040505522331 is a prime number
BaseRepresentation
bin1001001000011011110011…
…0000111101100010011011
31022112212022002111222121011
42102012330300331202123
52304000423403203311
633204313342554351
72054255041532164
oct222067460754233
938485262458534
1010040505522331
113221177680509
121161b00b989b7
1357aa7ab7760b
14269d6a8cc76b
1512629aed4321
hex921bcc3d89b

10040505522331 has 2 divisors, whose sum is σ = 10040505522332. Its totient is φ = 10040505522330.

The previous prime is 10040505522277. The next prime is 10040505522389. The reversal of 10040505522331 is 13322550504001.

10040505522331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10040505522331 - 213 = 10040505514139 is a prime.

It is a super-2 number, since 2×100405055223312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10040505522293 and 10040505522302.

It is not a weakly prime, because it can be changed into another prime (10040505522391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020252761165 + 5020252761166.

It is an arithmetic number, because the mean of its divisors is an integer number (5020252761166).

Almost surely, 210040505522331 is an apocalyptic number.

10040505522331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040505522331 is an equidigital number, since it uses as much as digits as its factorization.

10040505522331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 10040505522331 in words is "ten trillion, forty billion, five hundred five million, five hundred twenty-two thousand, three hundred thirty-one".