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10041014330257 is a prime number
BaseRepresentation
bin1001001000011101101100…
…0101111010001110010001
31022112220121112221002212011
42102013123011322032101
52304002444132032012
633204440040302521
72054303460402211
oct222073305721621
938486545832764
1010041014330257
113221408903429
121162023471a41
1357ab2c3c47b1
14269db82d8241
151262ca9dc1a7
hex921db17a391

10041014330257 has 2 divisors, whose sum is σ = 10041014330258. Its totient is φ = 10041014330256.

The previous prime is 10041014330233. The next prime is 10041014330317. The reversal of 10041014330257 is 75203341014001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10031054489856 + 9959840401 = 3167184^2 + 99799^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041014330257 - 223 = 10041005941649 is a prime.

It is not a weakly prime, because it can be changed into another prime (10041014330657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020507165128 + 5020507165129.

It is an arithmetic number, because the mean of its divisors is an integer number (5020507165129).

Almost surely, 210041014330257 is an apocalyptic number.

It is an amenable number.

10041014330257 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041014330257 is an equidigital number, since it uses as much as digits as its factorization.

10041014330257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 10041014330257 its reverse (75203341014001), we get a palindrome (85244355344258).

The spelling of 10041014330257 in words is "ten trillion, forty-one billion, fourteen million, three hundred thirty thousand, two hundred fifty-seven".