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10041042342131 is a prime number
BaseRepresentation
bin1001001000011101110011…
…0000110001000011110011
31022112220200111122020220222
42102013130300301003303
52304003023314422011
633204442520523255
72054304250450403
oct222073460610363
938486614566828
1010041042342131
1132214226a6139
12116203092052b
1357ab35151878
14269dbbd0a803
151262cd1c1ddb
hex921dcc310f3

10041042342131 has 2 divisors, whose sum is σ = 10041042342132. Its totient is φ = 10041042342130.

The previous prime is 10041042342077. The next prime is 10041042342169. The reversal of 10041042342131 is 13124324014001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10041042342131 - 238 = 9766164435187 is a prime.

It is a super-2 number, since 2×100410423421312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10041042342131.

It is not a weakly prime, because it can be changed into another prime (10041042342181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020521171065 + 5020521171066.

It is an arithmetic number, because the mean of its divisors is an integer number (5020521171066).

Almost surely, 210041042342131 is an apocalyptic number.

10041042342131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041042342131 is an equidigital number, since it uses as much as digits as its factorization.

10041042342131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 10041042342131 its reverse (13124324014001), we get a palindrome (23165366356132).

The spelling of 10041042342131 in words is "ten trillion, forty-one billion, forty-two million, three hundred forty-two thousand, one hundred thirty-one".