Base | Representation |
---|---|
bin | 1001001000011110001101… |
… | …1011111110010100101011 |
3 | 1022112220222022100221001221 |
4 | 2102013203123332110223 |
5 | 2304003241002110242 |
6 | 33204502001122511 |
7 | 2054310110400334 |
oct | 222074333762453 |
9 | 38486868327057 |
10 | 10041154331947 |
11 | 322147a936802 |
12 | 1162062329437 |
13 | 57ab5240282b |
14 | 269dccb3d28b |
15 | 1262d7e44167 |
hex | 921e36fe52b |
10041154331947 has 2 divisors, whose sum is σ = 10041154331948. Its totient is φ = 10041154331946.
The previous prime is 10041154331911. The next prime is 10041154332073. The reversal of 10041154331947 is 74913345114001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10041154331947 is a prime.
It is not a weakly prime, because it can be changed into another prime (10041154337947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020577165973 + 5020577165974.
It is an arithmetic number, because the mean of its divisors is an integer number (5020577165974).
Almost surely, 210041154331947 is an apocalyptic number.
10041154331947 is a deficient number, since it is larger than the sum of its proper divisors (1).
10041154331947 is an equidigital number, since it uses as much as digits as its factorization.
10041154331947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 43.
Adding to 10041154331947 its reverse (74913345114001), we get a palindrome (84954499445948).
The spelling of 10041154331947 in words is "ten trillion, forty-one billion, one hundred fifty-four million, three hundred thirty-one thousand, nine hundred forty-seven".
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