Base | Representation |
---|---|
bin | 11101001110010100100… |
… | …10111100000000001011 |
3 | 10112222210221110021210222 |
4 | 32213022102330000023 |
5 | 112422420030420323 |
6 | 2045141553100255 |
7 | 132355030403165 |
oct | 16471222740013 |
9 | 3488727407728 |
10 | 1004121341963 |
11 | 357933358133 |
12 | 14273225768b |
13 | 738c4093c1c |
14 | 36857945935 |
15 | 1b1bd4a99c8 |
hex | e9ca4bc00b |
1004121341963 has 2 divisors, whose sum is σ = 1004121341964. Its totient is φ = 1004121341962.
The previous prime is 1004121341933. The next prime is 1004121342043. The reversal of 1004121341963 is 3691431214001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1004121341963 - 214 = 1004121325579 is a prime.
It is not a weakly prime, because it can be changed into another prime (1004121341933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502060670981 + 502060670982.
It is an arithmetic number, because the mean of its divisors is an integer number (502060670982).
Almost surely, 21004121341963 is an apocalyptic number.
1004121341963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004121341963 is an equidigital number, since it uses as much as digits as its factorization.
1004121341963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
Adding to 1004121341963 its reverse (3691431214001), we get a palindrome (4695552555964).
The spelling of 1004121341963 in words is "one trillion, four billion, one hundred twenty-one million, three hundred forty-one thousand, nine hundred sixty-three".
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