Base | Representation |
---|---|
bin | 10010101101000000… |
… | …10011101101000011 |
3 | 221220210101001220211 |
4 | 21112200103231003 |
5 | 131031024310413 |
6 | 4340214414551 |
7 | 503555112154 |
oct | 112640235503 |
9 | 27823331824 |
10 | 10041244483 |
11 | 4293025666 |
12 | 1b42961457 |
13 | c403cb5aa |
14 | 6b381b92b |
15 | 3db80883d |
hex | 256813b43 |
10041244483 has 2 divisors, whose sum is σ = 10041244484. Its totient is φ = 10041244482.
The previous prime is 10041244471. The next prime is 10041244489. The reversal of 10041244483 is 38444214001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10041244483 - 221 = 10039147331 is a prime.
It is not a weakly prime, because it can be changed into another prime (10041244489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020622241 + 5020622242.
It is an arithmetic number, because the mean of its divisors is an integer number (5020622242).
Almost surely, 210041244483 is an apocalyptic number.
10041244483 is a deficient number, since it is larger than the sum of its proper divisors (1).
10041244483 is an equidigital number, since it uses as much as digits as its factorization.
10041244483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 10041244483 its reverse (38444214001), we get a palindrome (48485458484).
The spelling of 10041244483 in words is "ten billion, forty-one million, two hundred forty-four thousand, four hundred eighty-three".
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