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100421300224334 = 250210650112167
BaseRepresentation
bin10110110101010100100111…
…111011011000000101001110
3111011120011221002000102000002
4112311110213323120011032
5101130300310324134314
6553324524120404302
730103125302023535
oct2665244773300516
9434504832012002
10100421300224334
1129aa7485aa9361
12b31a3a2316692
1344058c364500b
141ab25b9c3931c
15b922c616aade
hex5b5527ed814e

100421300224334 has 4 divisors (see below), whose sum is σ = 150631950336504. Its totient is φ = 50210650112166.

The previous prime is 100421300224313. The next prime is 100421300224367. The reversal of 100421300224334 is 433422003124001.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 100421300224297 and 100421300224306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25105325056082 + ... + 25105325056085.

It is an arithmetic number, because the mean of its divisors is an integer number (37657987584126).

Almost surely, 2100421300224334 is an apocalyptic number.

100421300224334 is a deficient number, since it is larger than the sum of its proper divisors (50210650112170).

100421300224334 is an equidigital number, since it uses as much as digits as its factorization.

100421300224334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50210650112169.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 100421300224334 its reverse (433422003124001), we get a palindrome (533843303348335).

The spelling of 100421300224334 in words is "one hundred trillion, four hundred twenty-one billion, three hundred million, two hundred twenty-four thousand, three hundred thirty-four".

Divisors: 1 2 50210650112167 100421300224334