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1004220114151 = 5571802908643
BaseRepresentation
bin11101001110100000010…
…11101110010011100111
310120000001211022102210011
432213100023232103213
5112423120322123101
62045155442111051
7132360340062562
oct16472013562347
93500054272704
101004220114151
11357984090141
1214275b34b487
137390b6978c7
1436866ad74d9
151b1c6eba751
hexe9d02ee4e7

1004220114151 has 4 divisors (see below), whose sum is σ = 1006023023352. Its totient is φ = 1002417204952.

The previous prime is 1004220114137. The next prime is 1004220114169. The reversal of 1004220114151 is 1514110224001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1004220114151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004220114101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 901453765 + ... + 901454878.

It is an arithmetic number, because the mean of its divisors is an integer number (251505755838).

Almost surely, 21004220114151 is an apocalyptic number.

1004220114151 is a deficient number, since it is larger than the sum of its proper divisors (1802909201).

1004220114151 is an equidigital number, since it uses as much as digits as its factorization.

1004220114151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1802909200.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 1004220114151 its reverse (1514110224001), we get a palindrome (2518330338152).

The spelling of 1004220114151 in words is "one trillion, four billion, two hundred twenty million, one hundred fourteen thousand, one hundred fifty-one".

Divisors: 1 557 1802908643 1004220114151