Search a number
-
+
10042203113 is a prime number
BaseRepresentation
bin10010101101000111…
…11101101111101001
3221220212011202220122
421112203331233221
5131031300444423
64340251133025
7503566214045
oct112643755751
927825152818
1010042203113
11429361a918
121b43144175
13c40675a27
146b39cb025
153db9478c8
hex2568fdbe9

10042203113 has 2 divisors, whose sum is σ = 10042203114. Its totient is φ = 10042203112.

The previous prime is 10042203107. The next prime is 10042203139. The reversal of 10042203113 is 31130224001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10029621904 + 12581209 = 100148^2 + 3547^2 .

It is a cyclic number.

It is not a de Polignac number, because 10042203113 - 210 = 10042202089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10042203091 and 10042203100.

It is not a weakly prime, because it can be changed into another prime (10042203713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021101556 + 5021101557.

It is an arithmetic number, because the mean of its divisors is an integer number (5021101557).

Almost surely, 210042203113 is an apocalyptic number.

It is an amenable number.

10042203113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10042203113 is an equidigital number, since it uses as much as digits as its factorization.

10042203113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10042203113 its reverse (31130224001), we get a palindrome (41172427114).

The spelling of 10042203113 in words is "ten billion, forty-two million, two hundred three thousand, one hundred thirteen".