Base | Representation |
---|---|
bin | 1001001000100101010010… |
… | …0100101110000101010011 |
3 | 1022120002212121000022201102 |
4 | 2102021110210232011103 |
5 | 2304021132411401011 |
6 | 33205414204255015 |
7 | 2054405126211521 |
oct | 222112444560523 |
9 | 38502777008642 |
10 | 10043052450131 |
11 | 3222264317018 |
12 | 11624b1b4146b |
13 | 57b09572799c |
14 | 26a12cc77311 |
15 | 1263998ce73b |
hex | 9225492e153 |
10043052450131 has 2 divisors, whose sum is σ = 10043052450132. Its totient is φ = 10043052450130.
The previous prime is 10043052450121. The next prime is 10043052450163. The reversal of 10043052450131 is 13105425034001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10043052450131 is a prime.
It is a super-2 number, since 2×100430524501312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10043052450094 and 10043052450103.
It is not a weakly prime, because it can be changed into another prime (10043052450121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021526225065 + 5021526225066.
It is an arithmetic number, because the mean of its divisors is an integer number (5021526225066).
Almost surely, 210043052450131 is an apocalyptic number.
10043052450131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043052450131 is an equidigital number, since it uses as much as digits as its factorization.
10043052450131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 10043052450131 its reverse (13105425034001), we get a palindrome (23148477484132).
The spelling of 10043052450131 in words is "ten trillion, forty-three billion, fifty-two million, four hundred fifty thousand, one hundred thirty-one".
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