Base | Representation |
---|---|
bin | 11101001110101101100… |
… | …11101100000111100001 |
3 | 10120000100120102221022210 |
4 | 32213112303230013201 |
5 | 112423332300113431 |
6 | 2045214452152333 |
7 | 132363156543300 |
oct | 16472663540741 |
9 | 3500316387283 |
10 | 1004331254241 |
11 | 357a308a0357 |
12 | 1427906086a9 |
13 | 7392870bb83 |
14 | 36877788437 |
15 | 1b1d1b20d46 |
hex | e9d6cec1e1 |
1004331254241 has 96 divisors (see below), whose sum is σ = 1660689050112. Its totient is φ = 536450826240.
The previous prime is 1004331254237. The next prime is 1004331254249. The reversal of 1004331254241 is 1424521334001.
It is not a de Polignac number, because 1004331254241 - 22 = 1004331254237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1004331254199 and 1004331254208.
It is not an unprimeable number, because it can be changed into a prime (1004331254249) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 235701051 + ... + 235705311.
It is an arithmetic number, because the mean of its divisors is an integer number (17298844272).
Almost surely, 21004331254241 is an apocalyptic number.
It is an amenable number.
1004331254241 is a deficient number, since it is larger than the sum of its proper divisors (656357795871).
1004331254241 is a wasteful number, since it uses less digits than its factorization.
1004331254241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4919 (or 4912 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1004331254241 its reverse (1424521334001), we get a palindrome (2428852588242).
The spelling of 1004331254241 in words is "one trillion, four billion, three hundred thirty-one million, two hundred fifty-four thousand, two hundred forty-one".
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