100433232131 has 2 divisors, whose sum is σ = 100433232132. Its totient is φ = 100433232130.

The previous prime is 100433232101. The next prime is 100433232139. The reversal of 100433232131 is 131232334001.

It is a strong prime.

It is an emirp because it is prime and its reverse (131232334001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100433232131 - 2³⁴ = 83253362947 is a prime.

It is a super-2 number, since 2×100433232131² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 100433232097 and 100433232106.

It is not a weakly prime, because it can be changed into another prime (100433232139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50216616065 + 50216616066.

It is an arithmetic number, because the mean of its divisors is an integer number (50216616066).

Almost surely, 2^100433232131 is an apocalyptic number.

100433232131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100433232131 is an equidigital number, since it uses as much as digits as its factorization.

100433232131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 100433232131 its reverse (131232334001), we get a palindrome (231665566132).

The spelling of 100433232131 in words is "one hundred billion, four hundred thirty-three million, two hundred thirty-two thousand, one hundred thirty-one".