1004334401131 has 4 divisors (see below), whose sum is σ = 1004337431152. Its totient is φ = 1004331371112.

The previous prime is 1004334401113. The next prime is 1004334401167. The reversal of 1004334401131 is 1311044334001.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1004334401131 - 2¹¹ = 1004334399083 is a prime.

It is a super-2 number, since 2×1004334401131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1004334401096 and 1004334401105.

It is not an unprimeable number, because it can be changed into a prime (1004334404131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 946776 + ... + 1704421.

It is an arithmetic number, because the mean of its divisors is an integer number (251084357788).

Almost surely, 2^{1004334401131} is an apocalyptic number.

1004334401131 is a deficient number, since it is larger than the sum of its proper divisors (3030021).

1004334401131 is an equidigital number, since it uses as much as digits as its factorization.

1004334401131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3030020.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1004334401131 its reverse (1311044334001), we get a palindrome (2315378735132).

The spelling of 1004334401131 in words is "one trillion, four billion, three hundred thirty-four million, four hundred one thousand, one hundred thirty-one".