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10043412481 is a prime number
BaseRepresentation
bin10010101101010001…
…00101000000000001
3221220221110012212001
421112220211000001
5131032103144411
64340333104001
7503612411644
oct112650450001
927827405761
1010043412481
1142942764a3
121b43628001
13c409aa32b
146b3c23a5b
153dbad5dc1
hex256a25001

10043412481 has 2 divisors, whose sum is σ = 10043412482. Its totient is φ = 10043412480.

The previous prime is 10043412403. The next prime is 10043412487. The reversal of 10043412481 is 18421434001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7777652481 + 2265760000 = 88191^2 + 47600^2 .

It is an emirp because it is prime and its reverse (18421434001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10043412481 - 29 = 10043411969 is a prime.

It is a super-2 number, since 2×100434124812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10043412487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021706240 + 5021706241.

It is an arithmetic number, because the mean of its divisors is an integer number (5021706241).

Almost surely, 210043412481 is an apocalyptic number.

It is an amenable number.

10043412481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10043412481 is an equidigital number, since it uses as much as digits as its factorization.

10043412481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 10043412481 its reverse (18421434001), we get a palindrome (28464846482).

The spelling of 10043412481 in words is "ten billion, forty-three million, four hundred twelve thousand, four hundred eighty-one".