Base | Representation |
---|---|
bin | 11101001110111000001… |
… | …10101011111010001011 |
3 | 10120000120202122210111201 |
4 | 32213130012223322023 |
5 | 112424023022321303 |
6 | 2045231345005031 |
7 | 132365316103603 |
oct | 16473406537213 |
9 | 3500522583451 |
10 | 1004420120203 |
11 | 357a76a776a5 |
12 | 1427b6323777 |
13 | 73940c54896 |
14 | 368854bbc03 |
15 | 1b1d982681d |
hex | e9dc1abe8b |
1004420120203 has 2 divisors, whose sum is σ = 1004420120204. Its totient is φ = 1004420120202.
The previous prime is 1004420120183. The next prime is 1004420120261. The reversal of 1004420120203 is 3020210244001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1004420120203 - 29 = 1004420119691 is a prime.
It is a super-2 number, since 2×10044201202032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1004420120273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502210060101 + 502210060102.
It is an arithmetic number, because the mean of its divisors is an integer number (502210060102).
Almost surely, 21004420120203 is an apocalyptic number.
1004420120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004420120203 is an equidigital number, since it uses as much as digits as its factorization.
1004420120203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 1004420120203 its reverse (3020210244001), we get a palindrome (4024630364204).
The spelling of 1004420120203 in words is "one trillion, four billion, four hundred twenty million, one hundred twenty thousand, two hundred three".
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