Base | Representation |
---|---|
bin | 10110110101101000010011… |
… | …111110000100101011111011 |
3 | 111011122012111100122122002112 |
4 | 112311220103332010223323 |
5 | 101131122104144122413 |
6 | 553342341532122535 |
7 | 30104504206036241 |
oct | 2665502376045373 |
9 | 434565440578075 |
10 | 100442440223483 |
11 | 2a005443a82636 |
12 | b32250200644b |
13 | 44078b2266957 |
14 | 1ab36236b2791 |
15 | b92b1201e2a8 |
hex | 5b5a13f84afb |
100442440223483 has 2 divisors, whose sum is σ = 100442440223484. Its totient is φ = 100442440223482.
The previous prime is 100442440223467. The next prime is 100442440223519. The reversal of 100442440223483 is 384322044244001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100442440223483 - 24 = 100442440223467 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100442440223483.
It is not a weakly prime, because it can be changed into another prime (100442440423483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50221220111741 + 50221220111742.
It is an arithmetic number, because the mean of its divisors is an integer number (50221220111742).
Almost surely, 2100442440223483 is an apocalyptic number.
100442440223483 is a deficient number, since it is larger than the sum of its proper divisors (1).
100442440223483 is an equidigital number, since it uses as much as digits as its factorization.
100442440223483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 589824, while the sum is 41.
Adding to 100442440223483 its reverse (384322044244001), we get a palindrome (484764484467484).
The spelling of 100442440223483 in words is "one hundred trillion, four hundred forty-two billion, four hundred forty million, two hundred twenty-three thousand, four hundred eighty-three".
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