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10044442400131 is a prime number
BaseRepresentation
bin1001001000101010011101…
…1010111101010110000011
31022120020110110110002200001
42102022213122331112003
52304032004223301011
633210204135540431
72054454434456056
oct222124732752603
938506413402601
1010044442400131
113222907971027
12116281b52a717
1357b257697bc9
1426a2216d0a9d
1512642b93b7c1
hex922a76bd583

10044442400131 has 2 divisors, whose sum is σ = 10044442400132. Its totient is φ = 10044442400130.

The previous prime is 10044442400017. The next prime is 10044442400141. The reversal of 10044442400131 is 13100424444001.

10044442400131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10044442400131 - 29 = 10044442399619 is a prime.

It is a super-2 number, since 2×100444424001312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10044442400131.

It is not a weakly prime, because it can be changed into another prime (10044442400141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5022221200065 + 5022221200066.

It is an arithmetic number, because the mean of its divisors is an integer number (5022221200066).

Almost surely, 210044442400131 is an apocalyptic number.

10044442400131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10044442400131 is an equidigital number, since it uses as much as digits as its factorization.

10044442400131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 10044442400131 its reverse (13100424444001), we get a palindrome (23144866844132).

The spelling of 10044442400131 in words is "ten trillion, forty-four billion, four hundred forty-two million, four hundred thousand, one hundred thirty-one".