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100459940137 is a prime number
BaseRepresentation
bin101110110001111100…
…0010000100100101001
3100121022020002201111121
41131203320100210221
53121220221041022
6114052313055241
710154330254564
oct1354370204451
9317266081447
10100459940137
1139672020a17
12175779b7521
13961cba997b
144c101894db
15292e7dd2c7
hex1763e10929

100459940137 has 2 divisors, whose sum is σ = 100459940138. Its totient is φ = 100459940136.

The previous prime is 100459940123. The next prime is 100459940171. The reversal of 100459940137 is 731049954001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82118926096 + 18341014041 = 286564^2 + 135429^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100459940137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100459940093 and 100459940102.

It is not a weakly prime, because it can be changed into another prime (100459940117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50229970068 + 50229970069.

It is an arithmetic number, because the mean of its divisors is an integer number (50229970069).

Almost surely, 2100459940137 is an apocalyptic number.

It is an amenable number.

100459940137 is a deficient number, since it is larger than the sum of its proper divisors (1).

100459940137 is an equidigital number, since it uses as much as digits as its factorization.

100459940137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 136080, while the sum is 43.

The spelling of 100459940137 in words is "one hundred billion, four hundred fifty-nine million, nine hundred forty thousand, one hundred thirty-seven".