Base | Representation |
---|---|
bin | 1001001000110100001010… |
… | …0011000110001110100011 |
3 | 1022120111011211200222110022 |
4 | 2102031002203012032203 |
5 | 2304102322010032042 |
6 | 33211314310424055 |
7 | 2054606066305046 |
oct | 222150243061643 |
9 | 38514154628408 |
10 | 10047045002147 |
11 | 3223a22a8348a |
12 | 116322706202b |
13 | 57b58093c2ba |
14 | 26a3cb20cc5d |
15 | 126530182cd2 |
hex | 923428c63a3 |
10047045002147 has 2 divisors, whose sum is σ = 10047045002148. Its totient is φ = 10047045002146.
The previous prime is 10047045002143. The next prime is 10047045002167. The reversal of 10047045002147 is 74120054074001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10047045002147 - 22 = 10047045002143 is a prime.
It is a super-2 number, since 2×100470450021472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10047045002143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5023522501073 + 5023522501074.
It is an arithmetic number, because the mean of its divisors is an integer number (5023522501074).
Almost surely, 210047045002147 is an apocalyptic number.
10047045002147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10047045002147 is an equidigital number, since it uses as much as digits as its factorization.
10047045002147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31360, while the sum is 35.
Adding to 10047045002147 its reverse (74120054074001), we get a palindrome (84167099076148).
The spelling of 10047045002147 in words is "ten trillion, forty-seven billion, forty-five million, two thousand, one hundred forty-seven".
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