Base | Representation |
---|---|
bin | 101110110010101100… |
… | …1000001010011000001 |
3 | 100121100222211102021212 |
4 | 1131211121001103001 |
5 | 3121243214234122 |
6 | 114055020455505 |
7 | 10155056001311 |
oct | 1354531012301 |
9 | 317328742255 |
10 | 100485305537 |
11 | 39685376361 |
12 | 175843aa595 |
13 | 962521b296 |
14 | 4c136ad441 |
15 | 2931b4dce2 |
hex | 17656414c1 |
100485305537 has 2 divisors, whose sum is σ = 100485305538. Its totient is φ = 100485305536.
The previous prime is 100485305509. The next prime is 100485305579. The reversal of 100485305537 is 735503584001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100407230641 + 78074896 = 316871^2 + 8836^2 .
It is an emirp because it is prime and its reverse (735503584001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100485305537 - 232 = 96190338241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100485305494 and 100485305503.
It is not a weakly prime, because it can be changed into another prime (100485305507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50242652768 + 50242652769.
It is an arithmetic number, because the mean of its divisors is an integer number (50242652769).
Almost surely, 2100485305537 is an apocalyptic number.
It is an amenable number.
100485305537 is a deficient number, since it is larger than the sum of its proper divisors (1).
100485305537 is an equidigital number, since it uses as much as digits as its factorization.
100485305537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 41.
Adding to 100485305537 its reverse (735503584001), we get a palindrome (835988889538).
The spelling of 100485305537 in words is "one hundred billion, four hundred eighty-five million, three hundred five thousand, five hundred thirty-seven".
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