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10051110500593 is a prime number
BaseRepresentation
bin1001001001000011010011…
…0111101111100011110001
31022120212200011122200212211
42102100310313233203301
52304134133242004333
633213225540252121
72055111613416151
oct222206467574361
938525604580784
1010051110500593
113225719933658
121163b806a1041
1357ba7acb4596
1426a695132761
151266bc044ecd
hex92434def8f1

10051110500593 has 2 divisors, whose sum is σ = 10051110500594. Its totient is φ = 10051110500592.

The previous prime is 10051110500573. The next prime is 10051110500623. The reversal of 10051110500593 is 39500501115001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9814736591104 + 236373909489 = 3132848^2 + 486183^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10051110500593 is a prime.

It is not a weakly prime, because it can be changed into another prime (10051110500573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5025555250296 + 5025555250297.

It is an arithmetic number, because the mean of its divisors is an integer number (5025555250297).

Almost surely, 210051110500593 is an apocalyptic number.

It is an amenable number.

10051110500593 is a deficient number, since it is larger than the sum of its proper divisors (1).

10051110500593 is an equidigital number, since it uses as much as digits as its factorization.

10051110500593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3375, while the sum is 31.

Adding to 10051110500593 its reverse (39500501115001), we get a palindrome (49551611615594).

The spelling of 10051110500593 in words is "ten trillion, fifty-one billion, one hundred ten million, five hundred thousand, five hundred ninety-three".