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1005252124153 is a prime number
BaseRepresentation
bin11101010000011011011…
…00100001110111111001
310120002201202012222100211
432220031230201313321
5112432224020433103
62045450105431121
7132425041033234
oct16501554416771
93502652188324
101005252124153
11358363687572
121429a8a9b4a1
1373a44431904
1436923bb841b
151b2378c136d
hexea0db21df9

1005252124153 has 2 divisors, whose sum is σ = 1005252124154. Its totient is φ = 1005252124152.

The previous prime is 1005252124117. The next prime is 1005252124199. The reversal of 1005252124153 is 3514212525001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 959622037609 + 45630086544 = 979603^2 + 213612^2 .

It is an emirp because it is prime and its reverse (3514212525001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1005252124153 is a prime.

It is a super-2 number, since 2×10052521241532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1005252127153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502626062076 + 502626062077.

It is an arithmetic number, because the mean of its divisors is an integer number (502626062077).

Almost surely, 21005252124153 is an apocalyptic number.

It is an amenable number.

1005252124153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005252124153 is an equidigital number, since it uses as much as digits as its factorization.

1005252124153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 1005252124153 its reverse (3514212525001), we get a palindrome (4519464649154).

The spelling of 1005252124153 in words is "one trillion, five billion, two hundred fifty-two million, one hundred twenty-four thousand, one hundred fifty-three".