Search a number
-
+
10053131201 is a prime number
BaseRepresentation
bin10010101110011011…
…01001101111000001
3221221121201222102122
421113031221233001
5131042100144301
64341321254025
7504061130261
oct112715515701
927847658378
1010053131201
1142998042a3
121b46934315
13c42a00b59
146b52337a1
153dc8a581b
hex257369bc1

10053131201 has 2 divisors, whose sum is σ = 10053131202. Its totient is φ = 10053131200.

The previous prime is 10053131197. The next prime is 10053131227. The reversal of 10053131201 is 10213135001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6518947600 + 3534183601 = 80740^2 + 59449^2 .

It is a cyclic number.

It is not a de Polignac number, because 10053131201 - 22 = 10053131197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10053131201.

It is not a weakly prime, because it can be changed into another prime (10053131281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5026565600 + 5026565601.

It is an arithmetic number, because the mean of its divisors is an integer number (5026565601).

Almost surely, 210053131201 is an apocalyptic number.

It is an amenable number.

10053131201 is a deficient number, since it is larger than the sum of its proper divisors (1).

10053131201 is an equidigital number, since it uses as much as digits as its factorization.

10053131201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 10053131201 its reverse (10213135001), we get a palindrome (20266266202).

The spelling of 10053131201 in words is "ten billion, fifty-three million, one hundred thirty-one thousand, two hundred one".