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100531441 is a prime number
BaseRepresentation
bin1011111110111…
…11110011110001
321000011112012201
411333133303301
5201214001231
613550423201
72330334403
oct577376361
9230145181
10100531441
115182483a
1229801b01
1317a9b67a
14d4ccb73
158c5c161
hex5fdfcf1

100531441 has 2 divisors, whose sum is σ = 100531442. Its totient is φ = 100531440.

The previous prime is 100531433. The next prime is 100531447. The reversal of 100531441 is 144135001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100000000 + 531441 = 10000^2 + 729^2 .

It is a cyclic number.

It is not a de Polignac number, because 100531441 - 23 = 100531433 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100531447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50265720 + 50265721.

It is an arithmetic number, because the mean of its divisors is an integer number (50265721).

Almost surely, 2100531441 is an apocalyptic number.

It is an amenable number.

100531441 is a deficient number, since it is larger than the sum of its proper divisors (1).

100531441 is an equidigital number, since it uses as much as digits as its factorization.

100531441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 100531441 is about 10026.5368398067. The cubic root of 100531441 is about 464.9796746039.

Adding to 100531441 its reverse (144135001), we get a palindrome (244666442).

It can be divided in two parts, 100 and 531441, that multiplied together give a square (53144100 = 72902).

The spelling of 100531441 in words is "one hundred million, five hundred thirty-one thousand, four hundred forty-one".