Base | Representation |
---|---|
bin | 11101010000111001100… |
… | …01111100010010110111 |
3 | 10120010101101102121222210 |
4 | 32220130301330102313 |
5 | 112433233312420320 |
6 | 2045531150024503 |
7 | 132434233122465 |
oct | 16503461742267 |
9 | 3503341377883 |
10 | 1005505201335 |
11 | 358483522168 |
12 | 142a597a8133 |
13 | 73a849b0b1b |
14 | 36949655835 |
15 | 1b24ec120e0 |
hex | ea1cc7c4b7 |
1005505201335 has 16 divisors (see below), whose sum is σ = 1609050881376. Its totient is φ = 536188587648.
The previous prime is 1005505201331. The next prime is 1005505201397. The reversal of 1005505201335 is 5331025055001.
It is not a de Polignac number, because 1005505201335 - 22 = 1005505201331 is a prime.
It is a super-2 number, since 2×10055052013352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1005505201331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4950444 + ... + 5149553.
It is an arithmetic number, because the mean of its divisors is an integer number (100565680086).
Almost surely, 21005505201335 is an apocalyptic number.
1005505201335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1005505201335 is a deficient number, since it is larger than the sum of its proper divisors (603545680041).
1005505201335 is a wasteful number, since it uses less digits than its factorization.
1005505201335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10106642.
The product of its (nonzero) digits is 11250, while the sum is 30.
The spelling of 1005505201335 in words is "one trillion, five billion, five hundred five million, two hundred one thousand, three hundred thirty-five".
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