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100550520151 = 4121701113011
BaseRepresentation
bin101110110100101000…
…1110010110101010111
3100121112112112122220221
41131221101302311113
53121411413121101
6114105310335211
710156510214344
oct1355121626527
9317475478827
10100550520151
1139709169034
12175a21ba507
1396358a2903
144c1c2077cb
152937731aa1
hex1769472d57

100550520151 has 8 divisors (see below), whose sum is σ = 103008629808. Its totient is φ = 98092680000.

The previous prime is 100550520121. The next prime is 100550520167. The reversal of 100550520151 is 151025055001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100550520151 is a prime.

It is a super-2 number, since 2×1005505201512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100550520121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 833236 + ... + 946246.

It is an arithmetic number, because the mean of its divisors is an integer number (12876078726).

Almost surely, 2100550520151 is an apocalyptic number.

100550520151 is a deficient number, since it is larger than the sum of its proper divisors (2458109657).

100550520151 is a wasteful number, since it uses less digits than its factorization.

100550520151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134753.

The product of its (nonzero) digits is 1250, while the sum is 25.

Adding to 100550520151 its reverse (151025055001), we get a palindrome (251575575152).

The spelling of 100550520151 in words is "one hundred billion, five hundred fifty million, five hundred twenty thousand, one hundred fifty-one".

Divisors: 1 41 21701 113011 889741 4633451 2452451711 100550520151