Base | Representation |
---|---|
bin | 1001001001010010001011… |
… | …1111110101111000111011 |
3 | 1022121020222121010211110122 |
4 | 2102110202333311320323 |
5 | 2304220324013213313 |
6 | 33215130213203455 |
7 | 2055312614255354 |
oct | 222244277657073 |
9 | 38536877124418 |
10 | 10055105601083 |
11 | 3227389a807a4 |
12 | 11648b663058b |
13 | 57c2668abb7a |
14 | 26a95396cd2b |
15 | 126852b4d708 |
hex | 92522ff5e3b |
10055105601083 has 2 divisors, whose sum is σ = 10055105601084. Its totient is φ = 10055105601082.
The previous prime is 10055105600971. The next prime is 10055105601089. The reversal of 10055105601083 is 38010650155001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10055105601083 - 230 = 10054031859259 is a prime.
It is a super-2 number, since 2×100551056010832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10055105601089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5027552800541 + 5027552800542.
It is an arithmetic number, because the mean of its divisors is an integer number (5027552800542).
Almost surely, 210055105601083 is an apocalyptic number.
10055105601083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10055105601083 is an equidigital number, since it uses as much as digits as its factorization.
10055105601083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 35.
Adding to 10055105601083 its reverse (38010650155001), we get a palindrome (48065755756084).
The spelling of 10055105601083 in words is "ten trillion, fifty-five billion, one hundred five million, six hundred one thousand, eighty-three".
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