100560113 has 2 divisors, whose sum is σ = 100560114. Its totient is φ = 100560112.

The previous prime is 100560091. The next prime is 100560149. The reversal of 100560113 is 311065001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95023504 + 5536609 = 9748^2 + 2353^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100560113 is a prime.

It is a super-2 number, since 2×100560113² = 20224672653145538, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100560091 and 100560100.

It is not a weakly prime, because it can be changed into another prime (100560193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50280056 + 50280057.

It is an arithmetic number, because the mean of its divisors is an integer number (50280057).

Almost surely, 2^100560113 is an apocalyptic number.

It is an amenable number.

100560113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100560113 is an equidigital number, since it uses as much as digits as its factorization.

100560113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 100560113 is about 10027.9665436219. The cubic root of 100560113 is about 465.0238751375.

The spelling of 100560113 in words is "one hundred million, five hundred sixty thousand, one hundred thirteen".