100611104121331 has 4 divisors (see below), whose sum is σ = 102316377072600. Its totient is φ = 98905831170064.

The previous prime is 100611104121247. The next prime is 100611104121383. The reversal of 100611104121331 is 133121401116001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100611104121331 - 2³³ = 100602514186739 is a prime.

It is a super-3 number, since 3×100611104121331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100611104121296 and 100611104121305.

It is not an unprimeable number, because it can be changed into a prime (100611104151331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852636475546 + ... + 852636475663.

It is an arithmetic number, because the mean of its divisors is an integer number (25579094268150).

Almost surely, 2^{100611104121331} is an apocalyptic number.

100611104121331 is a deficient number, since it is larger than the sum of its proper divisors (1705272951269).

100611104121331 is an equidigital number, since it uses as much as digits as its factorization.

100611104121331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1705272951268.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 100611104121331 its reverse (133121401116001), we get a palindrome (233732505237332).

The spelling of 100611104121331 in words is "one hundred trillion, six hundred eleven billion, one hundred four million, one hundred twenty-one thousand, three hundred thirty-one".