Base | Representation |
---|---|
bin | 11110010001001010111101… |
… | …110100110101010101100001 |
3 | 122110100021121022220020112121 |
4 | 132101022331310311111201 |
5 | 114422030112141203001 |
6 | 1151043043304424241 |
7 | 40016463263342344 |
oct | 3621127564652541 |
9 | 573307538806477 |
10 | 133121401116001 |
11 | 3946451850a231 |
12 | 12b1b99ba78081 |
13 | 59383a964bb6c |
14 | 24c317852045b |
15 | 105cbd6ca86a1 |
hex | 7912bdd35561 |
133121401116001 has 2 divisors, whose sum is σ = 133121401116002. Its totient is φ = 133121401116000.
The previous prime is 133121401115887. The next prime is 133121401116029. The reversal of 133121401116001 is 100611104121331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130665360501025 + 2456040614976 = 11430895^2 + 1567176^2 .
It is a cyclic number.
It is not a de Polignac number, because 133121401116001 - 225 = 133121367561569 is a prime.
It is not a weakly prime, because it can be changed into another prime (133121401116061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66560700558000 + 66560700558001.
It is an arithmetic number, because the mean of its divisors is an integer number (66560700558001).
Almost surely, 2133121401116001 is an apocalyptic number.
It is an amenable number.
133121401116001 is a deficient number, since it is larger than the sum of its proper divisors (1).
133121401116001 is an equidigital number, since it uses as much as digits as its factorization.
133121401116001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 133121401116001 its reverse (100611104121331), we get a palindrome (233732505237332).
The spelling of 133121401116001 in words is "one hundred thirty-three trillion, one hundred twenty-one billion, four hundred one million, one hundred sixteen thousand, one".
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