Base | Representation |
---|---|
bin | 10110111010111001001011… |
… | …011100000000101110101011 |
3 | 111012220210010101210010102011 |
4 | 112322321023130000232223 |
5 | 101203033343401240324 |
6 | 554220441502420351 |
7 | 30142600522025566 |
oct | 2672711334005653 |
9 | 435823111703364 |
10 | 100804148071339 |
11 | 2a13488769a2a9 |
12 | b3806292916b7 |
13 | 4432a375b90ab |
14 | 1ac6d380334dd |
15 | b9c231d34c94 |
hex | 5bae4b700bab |
100804148071339 has 2 divisors, whose sum is σ = 100804148071340. Its totient is φ = 100804148071338.
The previous prime is 100804148071327. The next prime is 100804148071433. The reversal of 100804148071339 is 933170841408001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100804148071339 - 25 = 100804148071307 is a prime.
It is a super-2 number, since 2×1008041480713392 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100804148071292 and 100804148071301.
It is not a weakly prime, because it can be changed into another prime (100804148071309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50402074035669 + 50402074035670.
It is an arithmetic number, because the mean of its divisors is an integer number (50402074035670).
Almost surely, 2100804148071339 is an apocalyptic number.
100804148071339 is a deficient number, since it is larger than the sum of its proper divisors (1).
100804148071339 is an equidigital number, since it uses as much as digits as its factorization.
100804148071339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 49.
The spelling of 100804148071339 in words is "one hundred trillion, eight hundred four billion, one hundred forty-eight million, seventy-one thousand, three hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •