Base | Representation |
---|---|
bin | 11101011000110000101… |
… | …01110000000000100111 |
3 | 10120112021111222121210101 |
4 | 32230120111300000213 |
5 | 113020404232410130 |
6 | 2051510033204531 |
7 | 132643641402241 |
oct | 16543025600047 |
9 | 3515244877711 |
10 | 1009725669415 |
11 | 35a2498a9311 |
12 | 143837100747 |
13 | 742a81a5008 |
14 | 36c29d99091 |
15 | 1b3ea4d61ca |
hex | eb18570027 |
1009725669415 has 24 divisors (see below), whose sum is σ = 1278916873200. Its totient is φ = 765195462144.
The previous prime is 1009725669367. The next prime is 1009725669419. The reversal of 1009725669415 is 5149665279001.
It is not a de Polignac number, because 1009725669415 - 217 = 1009725538343 is a prime.
It is a super-3 number, since 3×10097256694153 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1009725669419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 28228572 + ... + 28264318.
It is an arithmetic number, because the mean of its divisors is an integer number (53288203050).
Almost surely, 21009725669415 is an apocalyptic number.
1009725669415 is a deficient number, since it is larger than the sum of its proper divisors (269191203785).
1009725669415 is a wasteful number, since it uses less digits than its factorization.
1009725669415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51439 (or 51420 counting only the distinct ones).
The product of its (nonzero) digits is 4082400, while the sum is 55.
The spelling of 1009725669415 in words is "one trillion, nine billion, seven hundred twenty-five million, six hundred sixty-nine thousand, four hundred fifteen".
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