Base | Representation |
---|---|
bin | 10010110100000000… |
… | …10000011101111011 |
3 | 222001212211200210011 |
4 | 21122000100131323 |
5 | 131141041421413 |
6 | 4350113002351 |
7 | 505200112456 |
oct | 113200203573 |
9 | 28055750704 |
10 | 10099951483 |
11 | 4313183046 |
12 | 1b5a5533b7 |
13 | c4c614b6b |
14 | 6bb54049d |
15 | 3e1a5333d |
hex | 25a01077b |
10099951483 has 2 divisors, whose sum is σ = 10099951484. Its totient is φ = 10099951482.
The previous prime is 10099951471. The next prime is 10099951493. The reversal of 10099951483 is 38415999001.
It is a strong prime.
It is an emirp because it is prime and its reverse (38415999001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10099951483 - 25 = 10099951451 is a prime.
It is not a weakly prime, because it can be changed into another prime (10099951453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5049975741 + 5049975742.
It is an arithmetic number, because the mean of its divisors is an integer number (5049975742).
Almost surely, 210099951483 is an apocalyptic number.
10099951483 is a deficient number, since it is larger than the sum of its proper divisors (1).
10099951483 is an equidigital number, since it uses as much as digits as its factorization.
10099951483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 349920, while the sum is 49.
The spelling of 10099951483 in words is "ten billion, ninety-nine million, nine hundred fifty-one thousand, four hundred eighty-three".
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