10100000001131 has 2 divisors, whose sum is σ = 10100000001132. Its totient is φ = 10100000001130.

The previous prime is 10100000001109. The next prime is 10100000001137. The reversal of 10100000001131 is 13110000000101.

It is a strong prime.

It is an emirp because it is prime and its reverse (13110000000101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10100000001131 - 2³⁰ = 10098926259307 is a prime.

It is a super-2 number, since 2×10100000001131² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100000001137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000000565 + 5050000000566.

It is an arithmetic number, because the mean of its divisors is an integer number (5050000000566).

Almost surely, 2^{10100000001131} is an apocalyptic number.

10100000001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100000001131 is an equidigital number, since it uses as much as digits as its factorization.

10100000001131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 10100000001131 its reverse (13110000000101), we get a palindrome (23210000001232).

The spelling of 10100000001131 in words is "ten trillion, one hundred billion, one thousand, one hundred thirty-one".