10100000103 has 4 divisors (see below), whose sum is σ = 13466666808. Its totient is φ = 6733333400.

The previous prime is 10100000087. The next prime is 10100000111. The reversal of 10100000103 is 30100000101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10100000103 - 2⁴ = 10100000087 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10100000091 and 10100000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10100001103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683333348 + ... + 1683333353.

It is an arithmetic number, because the mean of its divisors is an integer number (3366666702).

Almost surely, 2^10100000103 is an apocalyptic number.

10100000103 is a deficient number, since it is larger than the sum of its proper divisors (3366666705).

10100000103 is an equidigital number, since it uses as much as digits as its factorization.

10100000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3366666704.

The product of its (nonzero) digits is 3, while the sum is 6.

Adding to 10100000103 its reverse (30100000101), we get a palindrome (40200000204).

The spelling of 10100000103 in words is "ten billion, one hundred million, one hundred three", and thus it is an aban number.