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10100000110153 is a prime number
BaseRepresentation
bin1001001011111001011011…
…1010110011011001001001
31022202112212101002012011211
42102332112322303121021
52310434300012011103
633251513114253121
72061462263302042
oct222762672633111
938675771065154
1010100000110153
113244427834958
1211715457271a1
1358356c9a6135
1426cbb21bb8c9
15127ace1a036d
hex92f96eb3649

10100000110153 has 2 divisors, whose sum is σ = 10100000110154. Its totient is φ = 10100000110152.

The previous prime is 10100000110111. The next prime is 10100000110183. The reversal of 10100000110153 is 35101100000101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5393300233104 + 4706699877049 = 2322348^2 + 2169493^2 .

It is an emirp because it is prime and its reverse (35101100000101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10100000110153 is a prime.

It is a super-2 number, since 2×101000001101532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100000110103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000055076 + 5050000055077.

It is an arithmetic number, because the mean of its divisors is an integer number (5050000055077).

Almost surely, 210100000110153 is an apocalyptic number.

It is an amenable number.

10100000110153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100000110153 is an equidigital number, since it uses as much as digits as its factorization.

10100000110153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 10100000110153 its reverse (35101100000101), we get a palindrome (45201100110254).

The spelling of 10100000110153 in words is "ten trillion, one hundred billion, one hundred ten thousand, one hundred fifty-three".