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101000113303 = 195315795437
BaseRepresentation
bin101111000010000010…
…0110110110010010111
3100122200212112100210011
41132010010312302113
53123322012111203
6114222050541051
710203606540505
oct1360404666227
9318625470704
10101000113303
1139919a27021
12176a8897787
1396a7a8936b
144c61bdb675
152961e3e76d
hex1784136c97

101000113303 has 4 divisors (see below), whose sum is σ = 106315908760. Its totient is φ = 95684317848.

The previous prime is 101000113289. The next prime is 101000113321. The reversal of 101000113303 is 303311000101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303311000101 = 2313187434787.

It is a cyclic number.

It is not a de Polignac number, because 101000113303 - 25 = 101000113271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101000113103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2657897700 + ... + 2657897737.

It is an arithmetic number, because the mean of its divisors is an integer number (26578977190).

Almost surely, 2101000113303 is an apocalyptic number.

101000113303 is a deficient number, since it is larger than the sum of its proper divisors (5315795457).

101000113303 is an equidigital number, since it uses as much as digits as its factorization.

101000113303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5315795456.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 101000113303 its reverse (303311000101), we get a palindrome (404311113404).

The spelling of 101000113303 in words is "one hundred one billion, one hundred thirteen thousand, three hundred three".

Divisors: 1 19 5315795437 101000113303