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101001011100131 is a prime number
BaseRepresentation
bin10110111101110000100001…
…011000110111100111100011
3111020121121021010022011101202
4112331300201120313213203
5101214300032320201011
6554451120212351415
730163040132123132
oct2675604130674743
9436547233264352
10101001011100131
112a20031974760a
12b3b280a31556b
13444847ba3718c
141ad2691655919
15ba2404bab23b
hex5bdc216379e3

101001011100131 has 2 divisors, whose sum is σ = 101001011100132. Its totient is φ = 101001011100130.

The previous prime is 101001011100097. The next prime is 101001011100161. The reversal of 101001011100131 is 131001110100101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101001011100131 - 238 = 100726133193187 is a prime.

It is a super-2 number, since 2×1010010111001312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101001011100161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500505550065 + 50500505550066.

It is an arithmetic number, because the mean of its divisors is an integer number (50500505550066).

Almost surely, 2101001011100131 is an apocalyptic number.

101001011100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101001011100131 is an equidigital number, since it uses as much as digits as its factorization.

101001011100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 101001011100131 its reverse (131001110100101), we get a palindrome (232002121200232).

The spelling of 101001011100131 in words is "one hundred one trillion, one billion, eleven million, one hundred thousand, one hundred thirty-one".