Base | Representation |
---|---|
bin | 11101011001010010101… |
… | …10101000001001010001 |
3 | 10120120000102002121102121 |
4 | 32230221112220021101 |
5 | 113022000321041032 |
6 | 2051554231214241 |
7 | 132654005541355 |
oct | 16545126501121 |
9 | 3516012077377 |
10 | 1010011112017 |
11 | 35a385a3a596 |
12 | 1438b6817381 |
13 | 74322376a6b |
14 | 36c55c5d465 |
15 | 1b4155bba97 |
hex | eb295a8251 |
1010011112017 has 2 divisors, whose sum is σ = 1010011112018. Its totient is φ = 1010011112016.
The previous prime is 1010011111997. The next prime is 1010011112023. The reversal of 1010011112017 is 7102111100101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 916124636736 + 93886475281 = 957144^2 + 306409^2 .
It is an emirp because it is prime and its reverse (7102111100101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1010011112017 - 215 = 1010011079249 is a prime.
It is not a weakly prime, because it can be changed into another prime (1010011112417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505005556008 + 505005556009.
It is an arithmetic number, because the mean of its divisors is an integer number (505005556009).
Almost surely, 21010011112017 is an apocalyptic number.
It is an amenable number.
1010011112017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010011112017 is an equidigital number, since it uses as much as digits as its factorization.
1010011112017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 16.
Adding to 1010011112017 its reverse (7102111100101), we get a palindrome (8112122212118).
The spelling of 1010011112017 in words is "one trillion, ten billion, eleven million, one hundred twelve thousand, seventeen".
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