10100112220013 has 4 divisors (see below), whose sum is σ = 10100143031520. Its totient is φ = 10100081408508.

The previous prime is 10100112219997. The next prime is 10100112220021. The reversal of 10100112220013 is 31002221100101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10100112220013 - 2⁴ = 10100112219997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 10100112220013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10100112220043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14908703 + ... + 15571436.

It is an arithmetic number, because the mean of its divisors is an integer number (2525035757880).

Almost surely, 2^{10100112220013} is an apocalyptic number.

It is an amenable number.

10100112220013 is a deficient number, since it is larger than the sum of its proper divisors (30811507).

10100112220013 is an equidigital number, since it uses as much as digits as its factorization.

10100112220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30811506.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10100112220013 its reverse (31002221100101), we get a palindrome (41102333320114).

The spelling of 10100112220013 in words is "ten trillion, one hundred billion, one hundred twelve million, two hundred twenty thousand, thirteen".