10100120020153 has 2 divisors, whose sum is σ = 10100120020154. Its totient is φ = 10100120020152.

The previous prime is 10100120020087. The next prime is 10100120020181. The reversal of 10100120020153 is 35102002100101.

10100120020153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8617465544704 + 1482654475449 = 2935552^2 + 1217643^2 .

It is a cyclic number.

It is not a de Polignac number, because 10100120020153 - 2¹⁷ = 10100119889081 is a prime.

It is a super-3 number, since 3×10100120020153³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10100120020183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050060010076 + 5050060010077.

It is an arithmetic number, because the mean of its divisors is an integer number (5050060010077).

Almost surely, 2^{10100120020153} is an apocalyptic number.

It is an amenable number.

10100120020153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100120020153 is an equidigital number, since it uses as much as digits as its factorization.

10100120020153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 10100120020153 its reverse (35102002100101), we get a palindrome (45202122120254).

The spelling of 10100120020153 in words is "ten trillion, one hundred billion, one hundred twenty million, twenty thousand, one hundred fifty-three".