Base | Representation |
---|---|
bin | 10010110100000010… |
… | …10010010011000001 |
3 | 222001220100101122202 |
4 | 21122001102103001 |
5 | 131141124033441 |
6 | 4350122442545 |
7 | 505202314544 |
oct | 113201222301 |
9 | 28056311582 |
10 | 10100221121 |
11 | 4313347691 |
12 | 1b5a663455 |
13 | c4c6aa803 |
14 | 6bb5b085b |
15 | 3e1aa819b |
hex | 25a0524c1 |
10100221121 has 2 divisors, whose sum is σ = 10100221122. Its totient is φ = 10100221120.
The previous prime is 10100221093. The next prime is 10100221211. The reversal of 10100221121 is 12112200101.
Together with next prime (10100221211) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6453872896 + 3646348225 = 80336^2 + 60385^2 .
It is an emirp because it is prime and its reverse (12112200101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10100221121 - 26 = 10100221057 is a prime.
It is not a weakly prime, because it can be changed into another prime (10100221421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050110560 + 5050110561.
It is an arithmetic number, because the mean of its divisors is an integer number (5050110561).
Almost surely, 210100221121 is an apocalyptic number.
It is an amenable number.
10100221121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100221121 is an equidigital number, since it uses as much as digits as its factorization.
10100221121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 10100221121 its reverse (12112200101), we get a palindrome (22212421222).
The spelling of 10100221121 in words is "ten billion, one hundred million, two hundred twenty-one thousand, one hundred twenty-one".
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