Base | Representation |
---|---|
bin | 11101011001010101000… |
… | …11000000001000010001 |
3 | 10120120001210202210022221 |
4 | 32230222203000020101 |
5 | 113022020432230301 |
6 | 2052000224301041 |
7 | 132654340656226 |
oct | 16545243001021 |
9 | 3516053683287 |
10 | 1010031133201 |
11 | 35a396274822 |
12 | 143901471781 |
13 | 74326566a0c |
14 | 36c5879194d |
15 | 1b417223da1 |
hex | eb2a8c0211 |
1010031133201 has 2 divisors, whose sum is σ = 1010031133202. Its totient is φ = 1010031133200.
The previous prime is 1010031133187. The next prime is 1010031133259. The reversal of 1010031133201 is 1023311300101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 836538890625 + 173492242576 = 914625^2 + 416524^2 .
It is a cyclic number.
It is not a de Polignac number, because 1010031133201 - 213 = 1010031125009 is a prime.
It is a super-3 number, since 3×10100311332013 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1010031133261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505015566600 + 505015566601.
It is an arithmetic number, because the mean of its divisors is an integer number (505015566601).
Almost surely, 21010031133201 is an apocalyptic number.
It is an amenable number.
1010031133201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010031133201 is an equidigital number, since it uses as much as digits as its factorization.
1010031133201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1010031133201 its reverse (1023311300101), we get a palindrome (2033342433302).
The spelling of 1010031133201 in words is "one trillion, ten billion, thirty-one million, one hundred thirty-three thousand, two hundred one".
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